MySQL Assignment Help | Restore MySQL Database Using MySQL Administrator | Realcode4you

Updated: May 18, 2020



To run the code OPEN MYSQL Administrator, then click on Restore on the left of your screen.

Then click on open backup file and select the Employee_data.sql file.

After selecting the file click on Start Restore.

This process will create a database and tables.

Query1: Create three tables with relevant keys as suggested in the above diagram


Sol:-

Employee TABLE


DROP TABLE IF EXISTS `employee`;
CREATE TABLE `employee` (
 `employee_id` int(11) NOT NULL auto_increment,
  `Empname` varchar(25) NOT NULL,
 `Managerid` int(11) NOT NULL,
 `Dateofhire` date NOT NULL,
 `Jobname` varchar(15) NOT NULL,
 `Salary` decimal(10,2) NOT NULL,
 `department_id` int(11) NOT NULL,
 `DOB` date NOT NULL,
 `address` varchar(30) NOT NULL,
 PRIMARY KEY (`employee_id`),
 KEY `FK_employee_1` (`department_id`),
 CONSTRAINT `FK_employee_1` FOREIGN KEY (`department_id`) REFERENCES `department` (`department_id`)
) ENGINE=InnoDB AUTO_INCREMENT=1012 DEFAULT CHARSET=utf8;


Department TABLE

DROP TABLE IF EXISTS `department`;
CREATE TABLE `department` (
 `department_id` int(11) NOT NULL default '0',
 `Deptname` varchar(30) default NULL,
 `deptLocation` varchar(20) default NULL,
 `deptFloor` varchar(20) default NULL,
 PRIMARY KEY (`department_id`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
 

Salary TABLE

 
DROP TABLE IF EXISTS `salary`;
CREATE TABLE `salary` (
 `salary_level` int(11) NOT NULL default '0',
 `salarymin` int(11) default NULL,
 `salarymax` int(11) default NULL,
 PRIMARY KEY USING BTREE (`salary_level`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8;

Working with Queries


Query 2: Insert record of 10 employees in the employee table


Sol:-

INSERT INTO `employee` (`employee_id`,`Empname`,`Managerid`,`Dateofhire`,`Jobname`,`Salary`,`department_id`,`DOB`,`address`) VALUES 
 (1001,'Mark',5001,'2000-08-01','PROGRAMMER','90000.00',902,'1994-05-23','101 Park Street LA'),
 (1002,'Mary',5002,'2017-08-23','TESTER','100000.00',902,'1990-04-27','101 Mark Street LA'),
 (1003,'Faith',5003,'2018-06-10','HR MANAGER','25000.00',903,'1988-05-05','101 Royal casa LA'),
 (1004,'Natalia',5004,'2018-05-26','MANAGER','96000.00',903,'1994-06-28','101 Wardha LA'),
 (1005,'Flynn',5005,'2019-12-27','ELECTRICAL ENGG','56000.00',904,'1987-07-29','101 Uchha Kuaa LA'),
 (1006,'Max',5006,'2016-07-19','IT MANAGER','19000.00',901,'1994-03-10','101 Lal Kuwa LA'),
 (1007,'Ronny',5007,'2018-03-18','PROGRAMMER','27000.00',902,'1990-02-08','101 Mandi House LA'),
 (1008,'Sheing',5008,'2014-09-28','ELECTRICAL ENGG','34000.00',904,'1991-01-05','101 Opera Street LA'),
 (1009,'Robert',5009,'2019-07-05','MAINTENANCE','78400.00',905,'1993-07-21','101 Nariman House LA'),
 (1010,'Kareena',5010,'2015-06-03','TESTER','120000.00',902,'1994-08-24','101 Henton house LA'),
 (1011,'Janet',5095,'2014-10-12','PROGRAMMER','90000.00',2011,'1994-08-24','101 Henton house LA');

Query 3: Insert record of 5 departments in the department table

Sol:-

INSERT INTO `department` (`department_id`,`Deptname`,`deptLocation`,`deptFloor`) VALUES 
 (901,'IT','LONDON','1ST'),
 (902,'ENGG','LONDON','2ND'),
 (903,'HR','LONDON','3RD'),
 (904,'ELECTRICAL','LONDON','4TH'),
 (905,'MAINTENANCE','LONDON','5TH'),
 (2011,'PROGRAMMER1','PARIS','6TH');

Query 4: Insert record of 5 salary levels in the salary table

Sol:-

INSERT INTO `salary` (`salary_level`,`salarymin`,`salarymax`) VALUES

(1,15000,30000),

(2,30001,50000),

(3,50001,70000),

(4,70001,90000),

(5,90001,120000);

Query 5: Write a query to display the information about the employees in the employee

table

Sol:- SELECT * FROM employee e;



Query 6: Write a query to display the name of all the employees

Sol:- select Empname from EMPLOYEE;











Query 7: Write a query to display the name of all the employees and their jobname.

Sol:- select Empname, Jobname from EMPLOYEE;












Query 8: Write a query in SQL to display the unique jobname for all the employees

Sol:- select DISTINCT Jobname from EMPLOYEE;










Task 9: Write a query to increase the salary for all the employees by 12%. Display the

empname, jobname and salary after the increment

Sol:- SELECT Empname, Jobname, Salary + (Salary * 12/100) as NewSalary from EMPLOYEE;


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